Solution

Solution

Solution steps
Treat as a constant
Apply the Sum/Difference Rule:

Popular Examples

y^'=((e^{(x-y)}))/(1+e^x),y(1)=0d/(dt)(5e^t)tangent of f(x)=x^4-5x^2+4,\at x=1derivative of f(x)=x^3(x-9)^2derivative of 6x^5-15x^4+30x^2-30x+9

Frequently Asked Questions (FAQ)

  • What is (\partial)/(\partial x)(6y^9x^5-5y^8x^4) ?

    The answer to (\partial)/(\partial x)(6y^9x^5-5y^8x^4) is 30y^9x^4-20y^8x^3