What is the tangent of f(x)=-3x^2-3x+2,\at x=1 ?

The tangent of f(x)=-3x^2-3x+2,\at x=1 is y=-9x+5

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tangent of f(x)=-3x^2-3x+2,\at x=1

tangent of

f (x) = - 3 x^{2} - 3 x + 2, at x = 1

y = - 9 x + 5

Solution steps

Find the tangent point:

(1, - 4)

Find the slope of

f (x) = - 3 x^{2} - 3 x + 2 : \frac{df ( x )}{d x} = - 6 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 9

Find the line with slope m=

- 9

and passing through

(1, - 4) : y = - 9 x + 5

y = - 9 x + 5

What is the tangent of f(x)=-3x^2-3x+2,\at x=1 ?
The tangent of f(x)=-3x^2-3x+2,\at x=1 is y=-9x+5