What is the integral from 0 to 4 of (4x-4sqrt(x)) ?

The integral from 0 to 4 of (4x-4sqrt(x)) is 32/3

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integral from 0 to 4 of (4x-4sqrt(x))

\int_{0}^{4} (4 x - 4 x) d x

\frac{32}{3}

Decimal

10.66666 \dots

Solution steps

\int_{0}^{4} 4 x - 4 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 4 x d x - \int_{0}^{4} 4 x d x

\int_{0}^{4} 4 x d x = 32

\int_{0}^{4} 4 x d x = \frac{64}{3}

= 32 - \frac{64}{3}

Simplify

32 - \frac{64}{3} : \frac{32}{3}

= \frac{32}{3}

What is the integral from 0 to 4 of (4x-4sqrt(x)) ?
The integral from 0 to 4 of (4x-4sqrt(x)) is 32/3