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Popular Calculus >

y^'=e^{-y}(x^2-6)

Solution

y^{^{'}} = e^{- y} (x^{2} - 6)

Solution

y = ln (\frac{x ^{3}}{3} - 6 x + c_{1})

Solution steps

y^{'} (x) = e^{- y} (x^{2} - 6)

Solve separable ODE:

y = ln (\frac{x ^{3}}{3} - 6 x + c_{1})

y = ln (\frac{x ^{3}}{3} - 6 x + c_{1})

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-y}(x^2-6) ?
The solution for y^'=e^{-y}(x^2-6) is y=ln((x^3)/3-6x+c_{1})