What is (\partial)/(\partial z)(-yz) ?

The answer to (\partial)/(\partial z)(-yz) is -y

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(\partial)/(\partial z)(-yz)

\frac{\partial}{\partial z} (- yz)

- y

Solution steps

\frac{\partial}{\partial z} (- yz)

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= - y \cdot 1

Simplify

= - y

What is (\partial)/(\partial z)(-yz) ?
The answer to (\partial)/(\partial z)(-yz) is -y