What is the derivative of-2+7/(4x) ?

The derivative of-2+7/(4x) is -7/(4x^2)

What is the first derivative of-2+7/(4x) ?

The first derivative of-2+7/(4x) is -7/(4x^2)

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\frac{d}{d x} (- 2 + \frac{7}{4 x})

- \frac{7}{4 x ^{2}}

Solution steps

\frac{d}{d x} (- 2 + \frac{7}{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (2) + \frac{d}{d x} (\frac{7}{4 x})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (\frac{7}{4 x}) = - \frac{7}{4 x ^{2}}

= - 0 - \frac{7}{4 x ^{2}}

Simplify

= - \frac{7}{4 x ^{2}}

What is the derivative of-2+7/(4x) ?
The derivative of-2+7/(4x) is -7/(4x^2)
What is the first derivative of-2+7/(4x) ?
The first derivative of-2+7/(4x) is -7/(4x^2)