What is the solution for (dy)/(dx)+y^2-y=0 ?

The solution for (dy)/(dx)+y^2-y=0 is y=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy)/(dx)+y^2-y=0

\frac{d y}{d x} + y^{2} - y = 0

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

Solution steps

\frac{d y}{d x} + y^{2} - y = 0

Solve separable ODE:

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

What is the solution for (dy)/(dx)+y^2-y=0 ?
The solution for (dy)/(dx)+y^2-y=0 is y=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}