What is (\partial)/(\partial y)(3x^2+3y^2-15) ?

The answer to (\partial)/(\partial y)(3x^2+3y^2-15) is 6y

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(\partial)/(\partial y)(3x^2+3y^2-15)

\frac{\partial}{\partial y} (3 x^{2} + 3 y^{2} - 15)

6 y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} + 3 y^{2} - 15)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) + \frac{\partial}{\partial y} (3 y^{2}) - \frac{\partial}{\partial y} (15)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (3 y^{2}) = 6 y

\frac{\partial}{\partial y} (15) = 0

= 0 + 6 y - 0

Simplify

= 6 y

What is (\partial)/(\partial y)(3x^2+3y^2-15) ?
The answer to (\partial)/(\partial y)(3x^2+3y^2-15) is 6y