What is the integral of 10sin(x)2x ?

The integral of 10sin(x)2x is 20(-xcos(x)+sin(x))+C

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integral of 10sin(x)2x

\int 10 sin (x) 2 x d x

20 (- x cos (x) + sin (x)) + C

Solution steps

\int 10 sin (x) \cdot 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot 2 \cdot \int sin (x) x d x

Simplify

= 20 \cdot \int sin (x) x d x

Apply Integration By Parts

= 20 (- x cos (x) - \int - cos (x) d x)

\int - cos (x) d x = - sin (x)

= 20 (- x cos (x) - (- sin (x)))

Simplify

= 20 (- x cos (x) + sin (x))

Add a constant to the solution

= 20 (- x cos (x) + sin (x)) + C

What is the integral of 10sin(x)2x ?
The integral of 10sin(x)2x is 20(-xcos(x)+sin(x))+C