What is the solution for y^'=((y-xy))/(x^2) ?

The solution for y^'=((y-xy))/(x^2) is y=(e^{(-1+c_{1}x)/x})/(x)

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y^'=((y-xy))/(x^2)

y^{^{'}} = \frac{( y - x y )}{x ^{2}}

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

Solution steps

y^{'} (x) = \frac{( y - x y )}{x ^{2}}

Solve separable ODE:

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

y = \frac{e ^{\frac{- 1 + c _{1} x}{x}}}{x}

What is the solution for y^'=((y-xy))/(x^2) ?
The solution for y^'=((y-xy))/(x^2) is y=(e^{(-1+c_{1}x)/x})/(x)