derivative of |2x-1|

Lösung

\frac{d}{d x} (∣ 2 x - 1 ∣)

\frac{2 ( 2 x - 1 )}{∣ 2 x - 1 ∣}

Schritte zur Lösung

\frac{d}{d x} (∣ 2 x - 1 ∣)

Wende die Kettenregel an:

\frac{2 x - 1}{∣ ( 2 x - 1 ) ∣} \frac{d}{d x} (2 x - 1)

= \frac{2 x - 1}{∣ ( 2 x - 1 ) ∣} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= \frac{2 x - 1}{∣ ( 2 x - 1 ) ∣} \cdot 2

Multipliziere Brüche:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 ( 2 x - 1 )}{∣ 2 x - 1 ∣}

\frac{\partial}{\partial x} (\frac{( x - y )}{x + y})

\frac{d}{d x} ((x - 1)^{- 2})

y^{^{'}} + 3 y = 4 e^{- t}

x \to 10 - lim (\frac{1}{x - 10})

\int_{- 1}^{1} \frac{3 x}{( x + 5 ) ^{2}} d x