What is the derivative of 2cos(2x)+2sin(2x)+4x ?

The derivative of 2cos(2x)+2sin(2x)+4x is -4sin(2x)+4cos(2x)+4

What is the first derivative of 2cos(2x)+2sin(2x)+4x ?

The first derivative of 2cos(2x)+2sin(2x)+4x is -4sin(2x)+4cos(2x)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

2 cos (2 x) + 2 sin (2 x) + 4 x

- 4 sin (2 x) + 4 cos (2 x) + 4

Solution steps

\frac{d}{d x} (2 cos (2 x) + 2 sin (2 x) + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (2 x)) + \frac{d}{d x} (2 sin (2 x)) + \frac{d}{d x} (4 x)

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

\frac{d}{d x} (4 x) = 4

= - 4 sin (2 x) + 4 cos (2 x) + 4

What is the derivative of 2cos(2x)+2sin(2x)+4x ?
The derivative of 2cos(2x)+2sin(2x)+4x is -4sin(2x)+4cos(2x)+4
What is the first derivative of 2cos(2x)+2sin(2x)+4x ?
The first derivative of 2cos(2x)+2sin(2x)+4x is -4sin(2x)+4cos(2x)+4