What is the derivative of x^4-2ax^2-y+3 ?

The derivative of x^4-2ax^2-y+3 is 4x^3-4ax-(dy)/(dx)

What is the first derivative of x^4-2ax^2-y+3 ?

The first derivative of x^4-2ax^2-y+3 is 4x^3-4ax-(dy)/(dx)

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\frac{d}{d x} (x^{4} - 2 a x^{2} - y + 3)

4 x^{3} - 4 a x - \frac{d y}{d x}

Solution steps

\frac{d}{d x} (x^{4} - 2 a x^{2} - y + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 a x^{2}) - \frac{d y}{d x} + \frac{d}{d x} (3)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 a x^{2}) = 4 a x

\frac{d}{d x} (3) = 0

= 4 x^{3} - 4 a x - \frac{d y}{d x} + 0

Simplify

= 4 x^{3} - 4 a x - \frac{d y}{d x}

What is the derivative of x^4-2ax^2-y+3 ?
The derivative of x^4-2ax^2-y+3 is 4x^3-4ax-(dy)/(dx)
What is the first derivative of x^4-2ax^2-y+3 ?
The first derivative of x^4-2ax^2-y+3 is 4x^3-4ax-(dy)/(dx)