What is the limit as t approaches 0 of arctan(1/t) ?

The limit as t approaches 0 of arctan(1/t) is diverges

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limit as t approaches 0 of arctan(1/t)

t \to 0 lim (arctan (\frac{1}{t}))

diverges

Solution steps

t \to 0 lim (arctan (\frac{1}{t}))

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

t \to 0 + lim (arctan (\frac{1}{t})) = \frac{π}{2}

t \to 0 - lim (arctan (\frac{1}{t})) = - \frac{π}{2}

= diverges

What is the limit as t approaches 0 of arctan(1/t) ?
The limit as t approaches 0 of arctan(1/t) is diverges