integral from 0 to 3pi of 6x^2sin(1/6 x)

Lösung

\int_{0}^{3 π} 6 x^{2} sin (\frac{1}{6} x) d x

1296 (π - 2)

Dezimale

1479.50407 \dots

Schritte zur Lösung

\int_{0}^{3 π} 6 x^{2} sin (\frac{1}{6} x) d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{3 π} x^{2} sin (\frac{1}{6} x) d x

Wende U-Substitution an

= 6 \cdot \int_{0}^{\frac{π}{2}} 216 u^{2} sin (u) d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot 216 \cdot \int_{0}^{\frac{π}{2}} u^{2} sin (u) d u

Wende die partielle Integration an

= 6 \cdot 216 [- u^{2} cos (u) - \int - 2 u cos (u) d u]_{0}^{\frac{π}{2}}

\int - 2 u cos (u) d u = - 2 (u sin (u) + cos (u))

= 6 \cdot 216 [- u^{2} cos (u) - (- 2 (u sin (u) + cos (u)))]_{0}^{\frac{π}{2}}

Vereinfache

= 1296 [- u^{2} cos (u) + 2 (u sin (u) + cos (u))]_{0}^{\frac{π}{2}}

Berechne die Grenzen:

π - 2

= 1296 (π - 2)

\int_{0}^{6} - x^{2} + 6 x d x

d er i v a t i v e 20 x^{3}

ma c l a u r in f (x) = cos (2 x)

d er i v a t i v e f (x) = (x^{3} - 4)^{2} (2 x + 5)^{3}

\frac{d}{d x} (ln (5 x^{4} + 4 x))