integral of x^4sqrt(4+x^5)

Lösung

\int x^{4} 4 + x^{5} d x

\frac{2}{15} (4 + x^{5})^{\frac{3}{2}} + C

Schritte zur Lösung

\int x^{4} 4 + x^{5} d x

Wende U-Substitution an

= \int \frac{u}{5} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int u d u

Wende die Potenzregel an

= \frac{1}{5} \cdot \frac{2}{3} u^{\frac{3}{2}}

Setze in

u = 4 + x^{5}

ein

= \frac{1}{5} \cdot \frac{2}{3} (4 + x^{5})^{\frac{3}{2}}

Vereinfache

\frac{1}{5} \cdot \frac{2}{3} (4 + x^{5})^{\frac{3}{2}} : \frac{2}{15} (4 + x^{5})^{\frac{3}{2}}

= \frac{2}{15} (4 + x^{5})^{\frac{3}{2}}

Füge eine Konstante zur Lösung hinzu

= \frac{2}{15} (4 + x^{5})^{\frac{3}{2}} + C

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