What is the tangent of f(x)=sqrt(x+1),\at x=3 ?

The tangent of f(x)=sqrt(x+1),\at x=3 is y= 1/4 x+5/4

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tangent of f(x)=sqrt(x+1),\at x=3

tangent of

f (x) = x + 1, at x = 3

y = \frac{1}{4} x + \frac{5}{4}

Solution steps

Find the tangent point:

(3, 2)

Find the slope of

f (x) = x + 1 : \frac{df ( x )}{d x} = \frac{1}{2 x + 1}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(3, 2) : y = \frac{1}{4} x + \frac{5}{4}

y = \frac{1}{4} x + \frac{5}{4}

What is the tangent of f(x)=sqrt(x+1),\at x=3 ?
The tangent of f(x)=sqrt(x+1),\at x=3 is y= 1/4 x+5/4