y^{''}+5y^'=0

Lösung

y^{^{''}} + 5 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- 5 t}

Schritte zur Lösung

y^{''} (t) + 5 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 5 t}

y = c_{1} + c_{2} e^{- 5 t}

t an g e n t f (x) = x^{5}, at x = 1

\int \frac{( x + 1 )}{( x - 1 ) ^{2}} d x

\int \frac{sin ^{5} ( x )}{cos ^{2} ( x )} d x

\frac{\partial}{\partial x} (6 y e^{7 x})

\frac{d y}{d x} = (\frac{x}{y - 2})^{{3}} ln (2 x)