(\partial)/(\partial v)(u+2v)

Lösung

\frac{\partial}{\partial v} (u + 2 v)

2

Schritte zur Lösung

\frac{\partial}{\partial v} (u + 2 v)

Behandle

u

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial v} (u) + \frac{\partial}{\partial v} (2 v)

\frac{\partial}{\partial v} (u) = 0

\frac{\partial}{\partial v} (2 v) = 2

= 0 + 2

Vereinfache

= 2

\int_{1}^{2} \frac{v ^{6} + 4 v ^{8}}{v ^{5}} d v

y^{^{''}} + 4 y^{^{'}} - 16 y = 0

\frac{\partial}{\partial y} (3 x^{2} (1 + ln (y)))

x \to 0 lim (\frac{2 + x - 2}{x})

\frac{\partial}{\partial x} (13 - x^{2} - y^{2})