What is the derivative of e^{1+x^2}+3x^4 ?

The derivative of e^{1+x^2}+3x^4 is e^{1+x^2}*2x+12x^3

What is the first derivative of e^{1+x^2}+3x^4 ?

The first derivative of e^{1+x^2}+3x^4 is e^{1+x^2}*2x+12x^3

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derivative of

e^{1 + x^{2}} + 3 x^{4}

e^{1 + x^{2}} \cdot 2 x + 12 x^{3}

Solution steps

\frac{d}{d x} (e^{1 + x^{2}} + 3 x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{1 + x^{2}}) + \frac{d}{d x} (3 x^{4})

\frac{d}{d x} (e^{1 + x^{2}}) = e^{1 + x^{2}} \cdot 2 x

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

= e^{1 + x^{2}} \cdot 2 x + 12 x^{3}

What is the derivative of e^{1+x^2}+3x^4 ?
The derivative of e^{1+x^2}+3x^4 is e^{1+x^2}*2x+12x^3
What is the first derivative of e^{1+x^2}+3x^4 ?
The first derivative of e^{1+x^2}+3x^4 is e^{1+x^2}*2x+12x^3