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Beliebt Rechnen >

y^{''}+8y^'+25y=0,y(0)=4,y^'(0)=-14

Lösung

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y (0) = 4, y^{^{'}} (0) = - 14

Lösung

y = e^{- 4 t} (4 cos (3 t) + \frac{2}{3} sin (3 t))

Schritte zur Lösung

y^{''} (t) + 8 y^{'} (t) + 25 y = 0

Solve linear ODE:

y = e^{- 4 t} (4 cos (3 t) + \frac{2}{3} sin (3 t))

y = e^{- 4 t} (4 cos (3 t) + \frac{2}{3} sin (3 t))

Graph

Beliebte Beispiele

integral of a/x

(a(t)sin^3(t))^'

derivative y=sin(7x)

y^{''}+4y^'+17/4 y=0

(\partial)/(\partial x)(1-cos(x))