What is the integral of 9/32+9/8 x^2 ?

The integral of 9/32+9/8 x^2 is 9/32 x+(3x^3)/8+C

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integral of 9/32+9/8 x^2

\int \frac{9}{32} + \frac{9}{8} x^{2} d x

\frac{9}{32} x + \frac{3 x ^{3}}{8} + C

Solution steps

\int \frac{9}{32} + \frac{9}{8} x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{9}{32} d x + \int \frac{9}{8} x^{2} d x

\int \frac{9}{32} d x = \frac{9}{32} x

\int \frac{9}{8} x^{2} d x = \frac{3 x ^{3}}{8}

= \frac{9}{32} x + \frac{3 x ^{3}}{8}

Add a constant to the solution

= \frac{9}{32} x + \frac{3 x ^{3}}{8} + C

What is the integral of 9/32+9/8 x^2 ?
The integral of 9/32+9/8 x^2 is 9/32 x+(3x^3)/8+C