derivative 81m^8+2m^4+1

解答

导数

81 m^{8} + 2 m^{4} + 1

648 m^{7} + 8 m^{3}

求解步骤

\frac{d}{d m} (81 m^{8} + 2 m^{4} + 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d m} (81 m^{8}) + \frac{d}{d m} (2 m^{4}) + \frac{d}{d m} (1)

\frac{d}{d m} (81 m^{8}) = 648 m^{7}

\frac{d}{d m} (2 m^{4}) = 8 m^{3}

\frac{d}{d m} (1) = 0

= 648 m^{7} + 8 m^{3} + 0

化简

= 648 m^{7} + 8 m^{3}