What is the tangent of f(x)=x^3,\at x=1 ?

The tangent of f(x)=x^3,\at x=1 is y=3x-2

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tangent of f(x)=x^3,\at x=1

tangent of

f (x) = x^{3}, at x = 1

y = 3 x - 2

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = x^{3} : \frac{df ( x )}{d x} = 3 x^{2}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(1, 1) : y = 3 x - 2

y = 3 x - 2

What is the tangent of f(x)=x^3,\at x=1 ?
The tangent of f(x)=x^3,\at x=1 is y=3x-2