What is the derivative of (6x/(x+1)) ?

The derivative of (6x/(x+1)) is 6/((x+1)^2)

What is the first derivative of (6x/(x+1)) ?

The first derivative of (6x/(x+1)) is 6/((x+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (\frac{6 x}{x + 1})

\frac{6}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6 x}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{x}{x + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 6 \cdot \frac{\frac{d x}{d x} ( x + 1 ) - \frac{d}{d x} ( x + 1 ) x}{( x + 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + 1) = 1

= 6 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}}

Simplify

6 \cdot \frac{1 \cdot ( x + 1 ) - 1 \cdot x}{( x + 1 ) ^{2}} : \frac{6}{( x + 1 ) ^{2}}

= \frac{6}{( x + 1 ) ^{2}}

What is the derivative of (6x/(x+1)) ?
The derivative of (6x/(x+1)) is 6/((x+1)^2)
What is the first derivative of (6x/(x+1)) ?
The first derivative of (6x/(x+1)) is 6/((x+1)^2)