What is the solution for y^{'''}-y^{''}-20y^'=0 ?

The solution for y^{'''}-y^{''}-20y^'=0 is y=c_{1}+c_{2}e^{-4t}+c_{3}e^{5t}

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y^{'''}-y^{''}-20y^'=0

y^{^{'''}} - y^{^{''}} - 20 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- 4 t} + c_{3} e^{5 t}

Solution steps

y^{'''} (t) - y^{''} (t) - 20 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 t} + c_{3} e^{5 t}

y = c_{1} + c_{2} e^{- 4 t} + c_{3} e^{5 t}

What is the solution for y^{'''}-y^{''}-20y^'=0 ?
The solution for y^{'''}-y^{''}-20y^'=0 is y=c_{1}+c_{2}e^{-4t}+c_{3}e^{5t}