What is the derivative of 5/(x^4)+\sqrt[3]{x^2} ?

The derivative of 5/(x^4)+\sqrt[3]{x^2} is -(20)/(x^5)+(2x)/(3(x^2)^{2/3)}

What is the first derivative of 5/(x^4)+\sqrt[3]{x^2} ?

The first derivative of 5/(x^4)+\sqrt[3]{x^2} is -(20)/(x^5)+(2x)/(3(x^2)^{2/3)}

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derivative of

- \frac{20}{x ^{5}} + \frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (\frac{5}{x ^{4}}) = - \frac{20}{x ^{5}}

= - \frac{20}{x ^{5}} + \frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}}

What is the derivative of 5/(x^4)+\sqrt[3]{x^2} ?
The derivative of 5/(x^4)+\sqrt[3]{x^2} is -(20)/(x^5)+(2x)/(3(x^2)^{2/3)}
What is the first derivative of 5/(x^4)+\sqrt[3]{x^2} ?
The first derivative of 5/(x^4)+\sqrt[3]{x^2} is -(20)/(x^5)+(2x)/(3(x^2)^{2/3)}