derivative G(r)=sqrt(r)+\sqrt[4]{r}

Lösung

ableitung von

G (r) = r + 4 r

\frac{1}{2 r} + \frac{1}{4 r ^{\frac{3}{4}}}

Schritte zur Lösung

\frac{d}{d r} (r + 4 r)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d r} (r) + \frac{d}{d r} (4 r)

\frac{d}{d r} (r) = \frac{1}{2 r}

\frac{d}{d r} (4 r) = \frac{1}{4 r ^{\frac{3}{4}}}

= \frac{1}{2 r} + \frac{1}{4 r ^{\frac{3}{4}}}

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x \to - 3 lim (- 4 x + 8)

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