fläche ((3sqrt(x)))/2 ,3,2-(1/2 x)

Lösung

fläche

\frac{( 3 x )}{2}, 3, 2 - (\frac{1}{2} x)

\frac{17}{4}

Dezimale

4.25

Schritte zur Lösung

Um die Schnittpunkte zu finden, löse

f_{i} (x) = f_{j} (x)

\frac{( 3 x )}{2} = 2 - (\frac{1}{2} x) : x = 1

\frac{( 3 x )}{2} = 3 : x = 4

2 - (\frac{1}{2} x) = 3 : x = - 2

= \int_{- 2}^{1} ∣ f_{2} (x) - f_{3} (x) ∣ d x + \int_{1}^{4} ∣ f_{1} (x) - f_{3} (x) ∣ d x

= \int_{- 2}^{1} 2 - (\frac{1}{2} x) - 3 d x + \int_{1}^{4} \frac{( 3 x )}{2} - 3 d x

\int_{- 2}^{1} 2 - (\frac{1}{2} x) - 3 d x = \frac{9}{4}

\int_{1}^{4} \frac{( 3 x )}{2} - 3 d x = 2

= \frac{9}{4} + 2

Vereinfache

= \frac{17}{4}

\frac{d}{d x} (\frac{1 - 3 x}{5 + x})

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\frac{\partial}{\partial x} (- e^{c o s (x)} sin (x))

\frac{d}{d x} (100 x^{0.25} y^{0.75})

\int_{- 1}^{1} (e^{x} - (x^{2} - 2)) d x