What is the integral from 1 to 8 of \sqrt[3]{x}-1/x ?

The integral from 1 to 8 of \sqrt[3]{x}-1/x is 45/4-3ln(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 8 of \sqrt[3]{x}-1/x

\frac{45}{4} - 3 ln (2)

Decimal

9.17055 \dots

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{1}^{8} \frac{1}{x} d x = 3 ln (2)

= \frac{45}{4} - 3 ln (2)

What is the integral from 1 to 8 of \sqrt[3]{x}-1/x ?
The integral from 1 to 8 of \sqrt[3]{x}-1/x is 45/4-3ln(2)