(\partial)/(\partial y)(-1/2 x-3y+1)

Lösung

\frac{\partial}{\partial y} (- \frac{1}{2} x - 3 y + 1)

- 3

Schritte zur Lösung

\frac{\partial}{\partial y} (- \frac{1}{2} x - 3 y + 1)

Vereinfache

- \frac{1}{2} x - 3 y + 1 : - \frac{x}{2} - 3 y + 1

= \frac{\partial}{\partial y} (- \frac{x}{2} - 3 y + 1)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial y} (\frac{x}{2}) - \frac{\partial}{\partial y} (3 y) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (\frac{x}{2}) = 0

\frac{\partial}{\partial y} (3 y) = 3

\frac{\partial}{\partial y} (1) = 0

= - 0 - 3 + 0

Vereinfache

= - 3

\int u cos (u) d u

sin (x) sin (y) d x + cos (x) cos (y) d y = 0

\frac{\partial}{\partial y} (x^{2} e^{2 y})

x \to 4 - lim (\frac{2 x}{16 - x ^{2}})

\int_{0}^{3} x^{7} e^{x^{4}} d x