What is the integral of (4x-11)/(x^2-3x-4) ?

The integral of (4x-11)/(x^2-3x-4) is 3ln|x+1|+ln|x-4|+C

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integral of (4x-11)/(x^2-3x-4)

\int \frac{4 x - 11}{x ^{2} - 3 x - 4} d x

3 ln ∣ x + 1 ∣ + ln ∣ x - 4 ∣ + C

Solution steps

\int \frac{4 x - 11}{x ^{2} - 3 x - 4} d x

Take the partial fraction of

\frac{4 x - 11}{x ^{2} - 3 x - 4} : \frac{3}{x + 1} + \frac{1}{x - 4}

= \int \frac{3}{x + 1} + \frac{1}{x - 4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{x + 1} d x + \int \frac{1}{x - 4} d x

\int \frac{3}{x + 1} d x = 3 ln ∣ x + 1 ∣

\int \frac{1}{x - 4} d x = ln ∣ x - 4 ∣

= 3 ln ∣ x + 1 ∣ + ln ∣ x - 4 ∣

Add a constant to the solution

= 3 ln ∣ x + 1 ∣ + ln ∣ x - 4 ∣ + C

What is the integral of (4x-11)/(x^2-3x-4) ?
The integral of (4x-11)/(x^2-3x-4) is 3ln|x+1|+ln|x-4|+C