What is the integral from-32 to 8 of 1/(sqrt(|2x|)) ?

The integral from-32 to 8 of 1/(sqrt(|2x|)) is 12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-32 to 8 of 1/(sqrt(|2x|))

\int_{- 32}^{8} \frac{1}{∣ 2 x ∣} d x

12

Solution steps

\int_{- 32}^{8} \frac{1}{∣ 2 x ∣} d x

Eliminate Absolutes

= \int_{- 32}^{0} \frac{1}{- 2 x} d x + \int_{0}^{8} \frac{1}{2 x} d x

\int_{- 32}^{0} \frac{1}{- 2 x} d x = 8

\int_{0}^{8} \frac{1}{2 x} d x = 4

= 8 + 4

Simplify

= 12

What is the integral from-32 to 8 of 1/(sqrt(|2x|)) ?
The integral from-32 to 8 of 1/(sqrt(|2x|)) is 12