What is the tangent of f(x)=x^2+15x+56,\at x=2 ?

The tangent of f(x)=x^2+15x+56,\at x=2 is y=19x+52

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tangent of f(x)=x^2+15x+56,\at x=2

tangent of

f (x) = x^{2} + 15 x + 56, at x = 2

y = 19 x + 52

Solution steps

Find the tangent point:

(2, 90)

Find the slope of

f (x) = x^{2} + 15 x + 56 : \frac{df ( x )}{d x} = 2 x + 15

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 19

Find the line with slope m=

19

and passing through

(2, 90) : y = 19 x + 52

y = 19 x + 52

What is the tangent of f(x)=x^2+15x+56,\at x=2 ?
The tangent of f(x)=x^2+15x+56,\at x=2 is y=19x+52