What is the derivative of 2x^4-6x^3-7x^2+9 ?

The derivative of 2x^4-6x^3-7x^2+9 is 8x^3-18x^2-14x

What is the first derivative of 2x^4-6x^3-7x^2+9 ?

The first derivative of 2x^4-6x^3-7x^2+9 is 8x^3-18x^2-14x

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\frac{d}{d x} (2 x^{4} - 6 x^{3} - 7 x^{2} + 9)

8 x^{3} - 18 x^{2} - 14 x

Solution steps

\frac{d}{d x} (2 x^{4} - 6 x^{3} - 7 x^{2} + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (6 x^{3}) - \frac{d}{d x} (7 x^{2}) + \frac{d}{d x} (9)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (7 x^{2}) = 14 x

\frac{d}{d x} (9) = 0

= 8 x^{3} - 18 x^{2} - 14 x + 0

Simplify

= 8 x^{3} - 18 x^{2} - 14 x

What is the derivative of 2x^4-6x^3-7x^2+9 ?
The derivative of 2x^4-6x^3-7x^2+9 is 8x^3-18x^2-14x
What is the first derivative of 2x^4-6x^3-7x^2+9 ?
The first derivative of 2x^4-6x^3-7x^2+9 is 8x^3-18x^2-14x