What is the solution for 3xdx+4ydy=0 ?

The solution for 3xdx+4ydy=0 is y=(sqrt(-3x^2+c_{1)})/2 ,y=-(sqrt(-3x^2+c_{1)})/2

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3xdx+4ydy=0

3 x d x + 4 y d y = 0

y = \frac{- 3 x ^{2} + c _{1}}{2}, y = - \frac{- 3 x ^{2} + c _{1}}{2}

Solution steps

3 x d x + 4 y d y = 0

Solve separable ODE:

y = \frac{- 3 x ^{2} + c _{1}}{2}, y = - \frac{- 3 x ^{2} + c _{1}}{2}

y = \frac{- 3 x ^{2} + c _{1}}{2}, y = - \frac{- 3 x ^{2} + c _{1}}{2}

What is the solution for 3xdx+4ydy=0 ?
The solution for 3xdx+4ydy=0 is y=(sqrt(-3x^2+c_{1)})/2 ,y=-(sqrt(-3x^2+c_{1)})/2