What is the d/(dy)(e^{y^2}) ?

The d/(dy)(e^{y^2}) is e^{y^2}*2y

What is the first d/(dy)(e^{y^2}) ?

The first d/(dy)(e^{y^2}) is e^{y^2}*2y

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\frac{d}{d y} (e^{y^{2}})

e^{y^{2}} \cdot 2 y

Solution steps

\frac{d}{d y} (e^{y^{2}})

Apply the chain rule:

e^{y^{2}} \frac{d}{d y} (y^{2})

= e^{y^{2}} \frac{d}{d y} (y^{2})

\frac{d}{d y} (y^{2}) = 2 y

= e^{y^{2}} \cdot 2 y