What is the tangent of 16sqrt(x),\at x=16 ?

The tangent of 16sqrt(x),\at x=16 is y=2x+32

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tangent of 16sqrt(x),\at x=16

tangent of

16 x, at x = 16

y = 2 x + 32

Solution steps

Find the tangent point:

(16, 64)

Find the slope of

y = 16 x : \frac{d y}{d x} = \frac{8}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(16, 64) : y = 2 x + 32

y = 2 x + 32

What is the tangent of 16sqrt(x),\at x=16 ?
The tangent of 16sqrt(x),\at x=16 is y=2x+32