integral of (4x+3)/(sqrt(1-x^2))

解

\int \frac{4 x + 3}{1 - x ^{2}} d x

- 4 1 - x^{2} + 3 arcsin (x) + C

解答ステップ

\int \frac{4 x + 3}{1 - x ^{2}} d x

拡張

\frac{4 x + 3}{1 - x ^{2}} : \frac{4 x}{1 - x ^{2}} + \frac{3}{1 - x ^{2}}

= \int \frac{4 x}{1 - x ^{2}} + \frac{3}{1 - x ^{2}} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{4 x}{1 - x ^{2}} d x + \int \frac{3}{1 - x ^{2}} d x

\int \frac{4 x}{1 - x ^{2}} d x = - 4 1 - x^{2}

\int \frac{3}{1 - x ^{2}} d x = 3 arcsin (x)

= - 4 1 - x^{2} + 3 arcsin (x)

定数を解答に追加する

= - 4 1 - x^{2} + 3 arcsin (x) + C