Solution
Solution
Solution steps
Take the constant out:
Apply the Power Rule
Compute the boundaries:
Simplify
Popular Examples
limit as x approaches-2 of (x^2-5)/(2-x)integral from 0 to 1 of 6xarea y=e^x,y=x^2-1,x=-1,x=1sum from n=1 to infinity of ne^{6n}(dy)/(dt)-(3/t)*y=2t^3e^{2t},y(1)=0
Frequently Asked Questions (FAQ)
What is the integral from 1 to 6 of kx ?
The integral from 1 to 6 of kx is (35k)/2