What is the tangent of y=x^2+x,(-1,0) ?

The tangent of y=x^2+x,(-1,0) is y=-x-1

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tangent of y=x^2+x,(-1,0)

tangent of

y = x^{2} + x, (- 1, 0)

y = - x - 1

Solution steps

Find the slope of

y = x^{2} + x : \frac{d y}{d x} = 2 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

Find the line with slope m=

- 1

and passing through

(- 1, 0) : y = - x - 1

y = - x - 1