What is the solution for [x^2+y^2]dx=xydy ?

The solution for [x^2+y^2]dx=xydy is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}

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[x^2+y^2]dx=xydy

[x^{2} + y^{2}] d x = x y d y

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

Solution steps

[x^{2} + y^{2}] d x = x y d y

Solve Bernoulli ODE:

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

y = x 2 ln (x) + c_{1}, y = - x 2 ln (x) + c_{1}

What is the solution for [x^2+y^2]dx=xydy ?
The solution for [x^2+y^2]dx=xydy is y=xsqrt(2ln(x)+c_{1)},y=-xsqrt(2ln(x)+c_{1)}