What is the solution for y^'+y= 1/(1+t^2) ?

The solution for y^'+y= 1/(1+t^2) is y=(integral of \frac{e^t)/(1+t^2)}{e^t}

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y^'+y= 1/(1+t^2)

y^{^{'}} + y = \frac{1}{1 + t ^{2}}

y = \frac{\int \frac{e ^{t}}{1 + t ^{2}} d t}{e ^{t}}

Solution steps

y^{'} (t) + y = \frac{1}{1 + t ^{2}}

Solve linear ODE:

y = \frac{\int \frac{e ^{t}}{1 + t ^{2}} d t}{e ^{t}}

y = \frac{\int \frac{e ^{t}}{1 + t ^{2}} d t}{e ^{t}}

What is the solution for y^'+y= 1/(1+t^2) ?
The solution for y^'+y= 1/(1+t^2) is y=(integral of \frac{e^t)/(1+t^2)}{e^t}