What is the derivative of (8x^3-9/(x^2)) ?

The derivative of (8x^3-9/(x^2)) is (2(4x^3+9))/(x^3)

What is the first derivative of (8x^3-9/(x^2)) ?

The first derivative of (8x^3-9/(x^2)) is (2(4x^3+9))/(x^3)

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\frac{d}{d x} (\frac{8 x ^{3} - 9}{x ^{2}})

\frac{2 ( 4 x ^{3} + 9 )}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{8 x ^{3} - 9}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 8 x ^{3} - 9 ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( 8 x ^{3} - 9 )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (8 x^{3} - 9) = 24 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{24 x ^{2} x ^{2} - 2 x ( 8 x ^{3} - 9 )}{( x ^{2} ) ^{2}}

Simplify

\frac{24 x ^{2} x ^{2} - 2 x ( 8 x ^{3} - 9 )}{( x ^{2} ) ^{2}} : \frac{2 ( 4 x ^{3} + 9 )}{x ^{3}}

= \frac{2 ( 4 x ^{3} + 9 )}{x ^{3}}

What is the derivative of (8x^3-9/(x^2)) ?
The derivative of (8x^3-9/(x^2)) is (2(4x^3+9))/(x^3)
What is the first derivative of (8x^3-9/(x^2)) ?
The first derivative of (8x^3-9/(x^2)) is (2(4x^3+9))/(x^3)