derivative-16t^2+83t+4

Lösung

ableitung von

- 16 t^{2} + 83 t + 4

- 32 t + 83

Schritte zur Lösung

\frac{d}{d t} (- 16 t^{2} + 83 t + 4)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (16 t^{2}) + \frac{d}{d t} (83 t) + \frac{d}{d t} (4)

\frac{d}{d t} (16 t^{2}) = 32 t

\frac{d}{d t} (83 t) = 83

\frac{d}{d t} (4) = 0

= - 32 t + 83 + 0

Vereinfache

= - 32 t + 83

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