What is the derivative of-16t^2+83t+4 ?

The derivative of-16t^2+83t+4 is -32t+83

What is the first derivative of-16t^2+83t+4 ?

The first derivative of-16t^2+83t+4 is -32t+83

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derivative of

- 16 t^{2} + 83 t + 4

- 32 t + 83

Solution steps

\frac{d}{d t} (- 16 t^{2} + 83 t + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d t} (16 t^{2}) + \frac{d}{d t} (83 t) + \frac{d}{d t} (4)

\frac{d}{d t} (16 t^{2}) = 32 t

\frac{d}{d t} (83 t) = 83

\frac{d}{d t} (4) = 0

= - 32 t + 83 + 0

Simplify

= - 32 t + 83

What is the derivative of-16t^2+83t+4 ?
The derivative of-16t^2+83t+4 is -32t+83
What is the first derivative of-16t^2+83t+4 ?
The first derivative of-16t^2+83t+4 is -32t+83