What is (\partial)/(\partial x)(e^{2xyz-1}) ?

The answer to (\partial)/(\partial x)(e^{2xyz-1}) is e^{2xyz-1}*2yz

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(\partial)/(\partial x)(e^{2xyz-1})

\frac{\partial}{\partial x} (e^{2 x yz - 1})

e^{2 x yz - 1} \cdot 2 yz

Solution steps

\frac{\partial}{\partial x} (e^{2 x yz - 1})

Treat

y, z

as constants

Apply the chain rule:

e^{2 x yz - 1} \frac{\partial}{\partial x} (2 x yz - 1)

= e^{2 x yz - 1} \frac{\partial}{\partial x} (2 x yz - 1)

\frac{\partial}{\partial x} (2 x yz - 1) = 2 yz

= e^{2 x yz - 1} \cdot 2 yz

What is (\partial)/(\partial x)(e^{2xyz-1}) ?
The answer to (\partial)/(\partial x)(e^{2xyz-1}) is e^{2xyz-1}*2yz