What is the derivative of-8sin(2x) ?

The derivative of-8sin(2x) is -16cos(2x)

What is the first derivative of-8sin(2x) ?

The first derivative of-8sin(2x) is -16cos(2x)

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\frac{d}{d x} (- 8 sin (2 x))

- 16 cos (2 x)

Solution steps

\frac{d}{d x} (- 8 sin (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{d}{d x} (2 x)

= cos (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 8 cos (2 x) \cdot 2

Simplify

= - 16 cos (2 x)

What is the derivative of-8sin(2x) ?
The derivative of-8sin(2x) is -16cos(2x)
What is the first derivative of-8sin(2x) ?
The first derivative of-8sin(2x) is -16cos(2x)