What is the solution for y^{''}-8y+16=0 ?

The solution for y^{''}-8y+16=0 is y=c_{1}e^{2^{1+1/2}t}+c_{2}e^{-2^{1+1/2}t}+2

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y^{''}-8y+16=0

y^{^{''}} - 8 y + 16 = 0

y = c_{1} e^{2^{1 + \frac{1}{2}} t} + c_{2} e^{- 2^{1 + \frac{1}{2}} t} + 2

Solution steps

y^{''} (t) - 8 y + 16 = 0

Solve linear ODE:

y = c_{1} e^{2^{1 + \frac{1}{2}} t} + c_{2} e^{- 2^{1 + \frac{1}{2}} t} + 2

y = c_{1} e^{2^{1 + \frac{1}{2}} t} + c_{2} e^{- 2^{1 + \frac{1}{2}} t} + 2

What is the solution for y^{''}-8y+16=0 ?
The solution for y^{''}-8y+16=0 is y=c_{1}e^{2^{1+1/2}t}+c_{2}e^{-2^{1+1/2}t}+2