integral from-1 to 1 of x^3(1+x^4)^3

解答

\int_{- 1}^{1} x^{3} (1 + x^{4})^{3} d x

0

求解步骤

\int_{- 1}^{1} x^{3} (1 + x^{4})^{3} d x

如果 f(x) 是奇函数，并且在区间:

[- a, a]

范围内连续，则

\int_{- a}^{a} f (x) d x = 0

x^{3} (1 + x^{4})^{3}

的奇偶性:

奇

= 0

t an g e n t f (x) = 8 + 5 x^{2} - 2 x^{3}, (1, 11)

t an g e n t f (x) = \frac{4}{x}, (4, 1)

\int_{0}^{l n (3)} 2 (3 - x e^{x}) d x

\frac{d}{d x} (x^{4} + x^{3} + x^{2} + x + 1)

\int x 3^{x^{2}} d x