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Popular Calculus >

integral of 2x^2-8

Solution

\int 2 x^{2} - 8 d x

Solution

\frac{2 x ^{3}}{3} - 8 x + C

Solution steps

\int 2 x^{2} - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int 8 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 8 d x = 8 x

= \frac{2 x ^{3}}{3} - 8 x

Add a constant to the solution

= \frac{2 x ^{3}}{3} - 8 x + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 2x^2-8 ?
The integral of 2x^2-8 is (2x^3)/3-8x+C